Question

if sin theta is 3/5 and theta is an acute angle find the values of cos theta and tan theta.

Answer 1

Let theta be A
sin A= 3/5
Sin A=1/cos A
Cos A=1/sin A
=1/3/5
=5/3
Tan A=sin A/Cos A
=3/5/5/3
=1

Answer 2

$Cos \theta = \frac{Base}{Hypotenuse}=\frac{4}{5}$

$Tan\theta = \frac{Perpendicular}{base}=\frac{3}{4}$

Step-by-step explanation:

$Sin \theta = \frac{3}{5}$

$Sin \theta = \frac{Perpendicular}{Hypotenuse}$

On comparing

Perpendicular = 3

Hypotenuse = 5

$Hypotenuse^2 = Perpendicular^2+Base^2$

$5^2 = 3^2 +Base^2$

$\sqrt{5^2-3^2}=Base$

4=Base

$Cos \theta = \frac{Base}{Hypotenuse}=\frac{4}{5}$

$Tan\theta = \frac{Perpendicular}{base}=\frac{3}{4}$

#Learn more:

Given that tan theta = 5/12 and theta is acute angle , find sin theta and cos theta.

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