Question

If sin theta is equal to 1/2 then show that 3 cos theta - 4 cos cube theta is equal to zero.​

Answer 1

Step-by-step explanation:

Let theta be ₹.

sin ₹ = 1/2

sin ₹ = sin 30°

₹ = 30°

to prove:-

3cos₹ - 4cos^3₹ = 0

3cos30° - 4cos^3 30° = 0

3( \sqrt{3} /2) - 4( \sqrt{3} /2)^{3} = 03(

3

/2)−4(

3

/2)

3

=0

0 = 0

Hence Proved

I hope this answer is helpful