Math, asked by darshan3585, 11 months ago

if sin theta is equal to 1 by 3 then find the value of 2 cot square theta + 2

Answers

Answered by Anonymous
5
sin @ =1/3
2 cot^2@ +2=?
2 ( 1- cosec^2@)+2
2 - 2 cosec@ +2
2 cosec@
2 /sin@
2 /1/3
6

SAMARTHSSHETTY: thnx
Answered by wifilethbridge
2

2cot^{2} \theta +2=18

Step-by-step explanation:

Sin \theta = \frac{Perpendicular}{Hypotenuse}

We are given that Sin \theta = \frac{1}{3}

On comparing :

Perpendicular = 1

Hypotenuse = 3

Hypotenuse^2 = Perpendicular^2+Base^2\\3^2=1^2=base^2\\\sqrt{9-1}=Base \\\sqrt{8}=Base \\2 \sqrt{2}=Base

Cot \theta = \frac{Base}{Perpndicular}=2\sqrt{2}

2cot^{2} \theta +2=2(2\sqrt{2})^2+2=18

Hence 2cot^{2} \theta +2=18

#Learn more:

If sin theta is equal to 1 by 2 the find find the value of 3 Sin Theta - 4 sin cube theta​

https://brainly.in/question/13347361

Similar questions