Question

if sin theta is equal to 3/5 then the value of (1-cos square theta) is

Answer 1

Answer:

9/25

Step-by-step explanation:

sin theta is 3/5

sin square theta is (3/5)^2 which is 9/25

sin square theta + cos square theta = 1

therefore sin square theta = 1- cos square theta

Answer 2

Answer:

The required answer is $\frac{9}{25}$.

Step-by-step explanation:

According to the figure,

sinθ = $\frac{AB}{AC}$ = $\frac{3}{5}$

Using Pythagoras theorem, we find side BC.

BC= $\sqrt{AC^{2}-AB^{2} }$

=$\sqrt{5^{2}-3^{2} }$

=$\sqrt{16}$

=4

∴ BC = 4cm

cosθ =$\frac{BC}{AC}$ =$\frac{4}{5}$

We have to find the value of ($1- cos^{2}$θ)

($1- cos^{2}$θ)= 1- $(\frac{4}{5}) ^{2}$

=$\frac{25-16}{25}$

=$\frac{9}{25}$

The correct answer is $\frac{9}{25}$