If sin theta is equal to root 3 by 2 then (cosec theta+ cot theta)is equal to ? Without using the table.
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Answered by
6
Answer:
Hey Mate Here is ur Answer
sin @ = root3/2
cosec@+cot @ = ? --------(i)
1/ sin@ +cos @ /sin@ =
1 + cos@ /sin@ =
1+ cos @ /root3/2=
2 (1 + cos @)/root3 =
2 +2 cos@ = root3
2 cos @ = root 3 - 2
cos @= root3 -2 /2
On putting the value in the equation (i)
2/ root 3 + root3 -2/2/root 3 /2
2 /root 3+( root 3-2) / root 3
2+ root 3 -2 / root 3
root 3 / root 3
1
Answered by
2
Answer:
sin∅ = √3/2 which is equal to sin60°
∴ ∅ = 60°
∴ cosec∅ + cot∅ = cosec60° + cot60°
= 2/√3 + 1/√3
= 3/√3 hint: 3 = √3 x √3
=√3 is the answer
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