Question

if sin theta is equals to 4 by 5 then find the value of 3 sec theta minus 5 cos theta​

Answer 1

sin¢ = 4/5

So, cos¢ = √(1-sin^2¢)

cos¢ = √[ 1 - (4/5)^2 ]

cos¢ = √(1 - 16/25)

cos¢ = √(9/25)

cos¢ = 3/5...●

And , sec¢ = 1/cos¢

sec¢ = 5/3...●

Now, 3sec¢ - 5cos¢

= 3×(5/3) - 5×(3/5)

= 5 -3

= 2.......●

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Hope it was helpful.

Answer 2

Answer:

Step-by-step explanation:

Sintheta =4/5

P=4

h=5

b^2= h^2 - p^2

b^2= 25 - 16

b = 3

Costheta = 3/5

Sectheta = 5/3

Now

3sectheta - 5costheta

3*5/3 - 5*3/5

=5-3

=2