if sin theta is equals to 4 by 5 then find the value of 3 sec theta minus 5 cos theta
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Answered by
5
sin¢ = 4/5
So, cos¢ = √(1-sin^2¢)
cos¢ = √[ 1 - (4/5)^2 ]
cos¢ = √(1 - 16/25)
cos¢ = √(9/25)
cos¢ = 3/5...●
And , sec¢ = 1/cos¢
sec¢ = 5/3...●
Now, 3sec¢ - 5cos¢
= 3×(5/3) - 5×(3/5)
= 5 -3
= 2.......●
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Hope it was helpful.
Answered by
2
Answer:
Step-by-step explanation:
Sintheta =4/5
P=4
h=5
b^2= h^2 - p^2
b^2= 25 - 16
b = 3
Costheta = 3/5
Sectheta = 5/3
Now
3sectheta - 5costheta
3*5/3 - 5*3/5
=5-3
=2
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