if sin theta =x sec theta=y then find the value of cot theta
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sin theta = x
sec theta= y
cos theta= 1/sec theta
=1/y
Therefore, cot theta = cos theta/sin theta
= x/(1/y)
=x*y
=xy
sec theta= y
cos theta= 1/sec theta
=1/y
Therefore, cot theta = cos theta/sin theta
= x/(1/y)
=x*y
=xy
sullu81:
tq
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solution
sin∅=x sec∅=y ⇒cos∅=1/y
to find cot∅
⇒ there for tan∅=sin∅/cos∅
⇒tan∅=x/1/y
⇒tan∅=xy
there for to fin cot∅ we know that cot∅=1/tan∅
- ⇒ cot∅=1/tan∅
- ⇒cot∅=1/xy
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