If Sin * theta = X/Y then Cos '0' is
A. y/(sqrt(y ^ 2 - x ^ 2));
B. y/x;
C. x/(sqrt(y ^ 2 - x ^ 2))
D. (sqrt(y ^ 2 - x ^ 2))/y
plz answer me correctly yaar
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hey here is your answer in above pic
pls mark it as brainliest
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or sinθ=
sin θ = ⇒ =
⇒ =
side opposite to angle θ=AB=
hypotenuse AC=
In right angled △ABC, we have
⇒ + =⇒ +
⇒ ⇒=−(By Pythagoras theorem)
⇒ = =
(using identity − =(a+b)(a−b))
BC= = ±2xy
taking positie square root since, side cannot be negative
cosθ= = =
and tanθ= = =
so, = =
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