Question

if sin thita =5/13 and AC = 52cm find AB,BC and tan thita​

Answer 1

$question \: is \: wrong \\ because \: ab \: is \: given \: in \: question \\ \\ q1. \: if \: sinθ = \frac{5}{13} \: so \: find \: bc \: \\ and \: value \: of \: tanθ ? \\ \\ ans. \: \: sinθ = \frac{p}{h} = \frac{ opposite \: side \: to \:θ }{hypotenuse} = \frac{5}{13} \\ \\ so \: we \: know \: that \: we \: find \: base \: by \\ \: pythagoras \: theorem \\ - - > {h}^{2} = {p}^{2} + {b}^{2} \\ (ac)² = (ab )²+ (bc)² \\ (13)² = (5)² + (bc)² \\ 169 = 25 + (bc)² \\ 169 - 25 = (bc)² \\ 144 = (bc)² \\ \sqrt{12} \:² = bc \\ bc = 12 \\ \\ tanθ = \frac{p}{b } = \frac{opposite \: side \: to \:θ}{adjacent \: side \: to \:θ } = \frac{5}{12} \: \: \: \: ans.$