if sin thita=x^2-Y^2/x^2+Y^2 ,then find the value of cos thita and 1/tan thita
Answers
Answered by
0
Cos theta=under root 2 y^2/x^2+y^2
1/tan theta=under root 2 y ^2/x^2 - y^2
1/tan theta=under root 2 y ^2/x^2 - y^2
ashish364:
is this helpful for you guys
yes
thank you
but how u find base=root 2Y^2
Similar questions