Question

if sin tita =3/4, find Cos tita and Tan tita

Answer 1

$\huge\underline\bold\red{★Answer★}$

$sin \theta = \frac{3}{4} \\ cos \theta = \sqrt{1 - {sin}^{2} \theta } \\ = \sqrt{1 - \frac{9}{16} } \\ = \sqrt{ \frac{7}{16} } \\ = \frac{ \sqrt{7} }{4} \\ tan \theta = \frac{sin \theta }{cos \theta } = \frac{ \frac{3}{4} }{ \frac{ \sqrt{7} }{4} } = \frac{3}{ \sqrt{7} }$

Answer 2

$sin \: \theta = \frac{3}{4}$

$cos \: \theta = \sqrt{1 - {sin}^{2} \: \theta} \\ \\ cos \: \theta = \sqrt{1 - { (\frac{3}{4} )}^{2} } \\ \\ cos \: \theta = \sqrt{1 - \frac{9}{16} } \\ \\ cos \: \theta = \sqrt{ \frac{16 - 9}{16} } \\ \\ cos \: \theta = \sqrt{ \frac{7}{16} } \\ \\ = \frac {\sqrt 7}{4}$

$tan \: \theta = \frac{sin\: \theta}{cos \: \theta}= \frac{\frac{3}{4}}{\frac{\sqrt 7}{4}} = \frac{3}{\sqrt 7}$