If sin x=1/3 then what is the value of cos x?
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Cosx=√1-sin^2x
cosx=√1-(1÷3)^2
cosx =√1-1÷9
cosx=√9-1÷9
cosx=√8÷9
cosx=√8÷3
cosx=√1-(1÷3)^2
cosx =√1-1÷9
cosx=√9-1÷9
cosx=√8÷9
cosx=√8÷3
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