Question

If sin x =12/13 and sin y = 4/5, fin the value of tan(x-y)
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Answer 1

Answer:

sinx = 12/13, so tanx = 12/5

siny = 4/5, so tany = 4/3

$tan(x - y) = \frac{tanx - tany}{1 - tanx \: tany} \\ = \frac{ \frac{12}{5} - \frac{4}{3} }{1 + \frac{12}{5} \times \frac{4}{3} } \\ = \frac{36 - 20}{15 + 48} \\ = \frac{16}{63}$

Answer 2

Answer:

16/63

Step-by-step explanation:

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