If sin x = 12/13 and x lies in the 2nd quadrant. Show that, sec x + tan x = -5
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Sin x= 12/13
By pythagorus theorem
Base = 5 cm
Now x lies is second quad
So sec x=- 13/5
Tanx=-12/5
Now sec x+ tan x= -13/5-12/5
= -25/5
= -5 proved...
By pythagorus theorem
Base = 5 cm
Now x lies is second quad
So sec x=- 13/5
Tanx=-12/5
Now sec x+ tan x= -13/5-12/5
= -25/5
= -5 proved...
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