Question

. If sin x = 20/29 find cosx​

Answer 1

Given,

sin \thetaθ = \frac{20}{29}

29

20

= \frac{b}{c}

c

b

\implies a=\sqrt{c^{2}-b^{2}}⟹a=

c

2

−b

2

\implies\sqrt{29^{2}-20^{2}}⟹

29

2

−20

2

\implies\sqrt{441}⟹

441

\implies 21⟹21

Now, cos \thetaθ = \frac{a}{c}

c

a

= \frac{21}{29}

29

21...