CBSE BOARD X, asked by ansh5004, 11 months ago

If sin (x-20)=cos(3x-10),thenfind the value of x

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Answered by gujjarritik008

0

cos[90-(x-20)] =cos(3x-10) because cosФ =sin (90-Ф) 90-x+20=3x-10 110-x=3x-10 110+10=x+3x 120/4=x x==30

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