Question

If sin x=3/5 and x>90 determine the value of sin 2x

Answer 1

Answer:

Given,

sin x=3/5=Perpendicular/Hypotenuse

By applying Pythagoras theorem,

(Hypotenuse)^2=(Perpendicular)^2+(Base)^2

(5)^2=(3)^2+(Base)^2

25-9=(Base)^2

√16=Base

Base=4

Now,

cos x= Base/Hypotenuse=4/5

Now,

sin2x=2sinxcosx=2×3/5×4/5=24/25