If sin x-cos x =0 then find the value of sin4x+cos4x =?
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Answered by
11
sinx - cosx = 0
By squaring both the sides
sin2x + cos2x - 2 sinx cosx = 0 ........ (1)
1 - 2 sinx cosx = 0 or 2 sinx cosx = 1
again by squaring (1)
(sin2x + cos2x - 1)2 = (0)2
sin4x + cos4x + 1 + 2 sin2x cos2x - 2 cos2x - 2 sin2x = 0
sin4x + cos4x + 1 + 2(1) - 2 (1 - sin2x) - 2 sin2x = 0
sin4x + cos4x + 1 + 2 - 2 + 2 sin2x - 2 sin2x = 0
sin4x + cos4x + 1 = 0
sin4x + cos4x = -1
Hope it helps !!!
By squaring both the sides
sin2x + cos2x - 2 sinx cosx = 0 ........ (1)
1 - 2 sinx cosx = 0 or 2 sinx cosx = 1
again by squaring (1)
(sin2x + cos2x - 1)2 = (0)2
sin4x + cos4x + 1 + 2 sin2x cos2x - 2 cos2x - 2 sin2x = 0
sin4x + cos4x + 1 + 2(1) - 2 (1 - sin2x) - 2 sin2x = 0
sin4x + cos4x + 1 + 2 - 2 + 2 sin2x - 2 sin2x = 0
sin4x + cos4x + 1 = 0
sin4x + cos4x = -1
Hope it helps !!!
Answered by
0
Answer:
The Answer is 1/2.
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