If Sin x = Cos² x , Then write The value of Cos²x ( 1 + cos²x )
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Given
sinx = cos^2x
Now
sin^2x - sinx - 1=0
let sinx = t
t^2 -t -1=0
sinx = t = (1+sqrt5)/2and( 1 - sqrt5)/2
Cos²x ( 1 + cos²x )
sinx(1+sinx)
sinx + sin^2x
(1+sqrt5)/2 +{ (1+sqrt5)/2 }^2
1
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