If sin x + sin^2x =1 than find the value of cos^8x + 2cos^6 + cos^4x
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check the answer will be 1
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Step-by-step explanation:
sinX+sin²x =1
=>sinx = 1-sin²x
=cos²x
cos^8x+cos^4x+2cos^6x
=cos²(cos⁴x+cos²x+2cos^6)
=cos²(cos²x+cosX)²
[using indices]
=sinx(sin⁴x+sinx)
=sin^5x+sin²x.
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