Math, asked by PavanKumarG858, 10 months ago

If sin x + cos x =m and sec x + cosec x = n prove that n(m^2 - 1) = 2

Answers

Answered by sonuo2
1

Answer

perfect answer for n(m^2 - 1) will be 2m yaar but not m

Explanation

Given,sin x + cos x =m and sec x + cosec x = n

n(m^2 - 1)=(sec x + cosec x)[(sin x + cos x)^2-1]

=[(sinx+cosx)/sinxcosx](sin^2x+cos^2x+2sinxcosx-1)

=[(sinx+cosx)/sinxcosx](1+2sinxcosx-1)

=[(sinx+cosx)/sinxcosx](2sinxcosx)

=(sinx+cosx)2

=2m

Answered by brunoconti
1

Answer:

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