if sin x+sin y=√3(cos y-cos x) prove that sin3x+sin3y=0
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Given
sinx+siny=√3(cosy−cosx)
2sin(x+y/2)cos(x−y/2)=√3⋅2sin(x+y/2)sin(x−y/2)
⇒sin(x+y/2)cos(x−y/2)−√3sin(x+y/2)sin(x−y/2)=0
⇒sin(x+y/2)[cos(x−y/2)−√3sin(x−y/2)]=0
So
sin(x+y/2)=0
⇒x+y/2=0
Now
sin3x+sin3y
=2sin(3(x+y)/2)cos(3(x−y)/2)
=2sin(3⋅0)cos(3(x−y)/2)
=0
hope it's helpful
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