Question

if sin2[2/1,3/2,4/3........….x-1/x-2]=1 then the value of x is ​

Answer 1

$\displaystyle\large\boxed{\sf{(D)\quad\!46^o}}$

$\displaystyle\longrightarrow\sf{\sin\left[2\left(\dfrac{2}{1}\cdot\dfrac{3}{2}\cdot\dfrac{4}{3}\cdot\ \dots\ \cdot\dfrac{x-2}{x-3}\cdot\dfrac{x-1}{x-2}\right)\right]=1}$

$\displaystyle\longrightarrow\sf{\sin[2(x-1)]=\sin90^o}$

$\displaystyle\longrightarrow\sf{2(x-1)=90^o}$

$\displaystyle\longrightarrow\sf{x-1=45^o}$

$\displaystyle\longrightarrow\sf{\underline{\underline{x=46^o}}}$

Answer 2

Answer:46

Step-by-step explanation: