if sin2A=0.6,find the value of tanA
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Sin2A = 3/5 ...
Sin2A = (2 tanA ) / ( 1 + tan^2A )
3 tan^2A -10 tanA + 3 = 0
tanA = 3 or tanA = 1/3 .....
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Sin2A = (2 tanA ) / ( 1 + tan^2A )
3 tan^2A -10 tanA + 3 = 0
tanA = 3 or tanA = 1/3 .....
I think it helps uuuuu☺☺☺☺
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