Math, asked by krishsharma76097609, 3 months ago

If sin2A=1/2 (tan245°), where A is an acute angle, then the value of A is:​

Answers

Answered by shivakants058
0

Answer:

45°

Step-by-step explanation:

sin^2 A = 1/2 tan^2 45°. value of tan 45° = 1

so , sin^2A = 1/2(1)

sin^2 A = 1/2

sin A = 1/√2

so , angle A = 45°

Answered by singhrishabhrenu36
0

Answer:

Step-by-step explanation:

Sin^2A = 1/2tan^2 45° = sin^a=1/2(1)^2

[Since tan 45°=1 ]

Sin^2A=1/2 = sinA=1/√2

Hence a= 45°

Here is a step by step solution

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