If Sin2A = 2Sin A = 2Sin A than A is equal to (a) 0 (b) 2 (c) 1 (d) 3
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Answered by
31
given
Sin 2A = 2 SinA
by double angle formula
2SinA CosA = 2 SinA
2SinA(CosA-1)=0
2 SinA =0 or CosA 1=0
SinA =0 or CosA=1
∴ SinA =0
Sin 2A = 2 SinA
by double angle formula
2SinA CosA = 2 SinA
2SinA(CosA-1)=0
2 SinA =0 or CosA 1=0
SinA =0 or CosA=1
∴ SinA =0
Answered by
10
answer : option (a)
explanation : it is given that, sin2A = 2sinA.
we know, sin(A + B) = sinA.cosB + cosA.sinB
if A = B
then, sin(A + A) = sinA.cosA + sinA.cosA
or, sin2A = 2sinA.cosA use this application in above equation.
so, sin2A = 2sinA.cosA = 2sinA.
or, 2sinA.cosA - 2sinA = 0
or, 2sinA(cosA - 1) = 0
sinA = 0 and cosA = 1
for sinA = 0
A = 0, π, 2π, 3π, -π, -2π, ......
for cosA = 1
A = 0, 2π, 4π, 6π, -2π, -4π, .....
common values of A = 0, 2π, 4π, ...
in option (a), it is given that value of A = 0,
so, option (a) is correct choice.
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