If sin²a + sina = 1 then prove that
Cos¹²a + 3Cos^10 a+ 3cos^8 a + cos^6 a-1 = 0.
I am using a in the place of theta.
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cos12 a +3cos 10a+3cos 8a+cos 6a-1
can be written as [cos^2 a + cos^4 a]^3 - 1
from given equation sin^2 a = 1 - sin a => cos^2 a = sin a
=> [ sina a + sin^2 a ]^3 - 1
=> 1^3 - 1
=> 0
hope it explains !!
arsh2006india:
most welcome
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