If sin3 theta= cos ( theta - 6)where 3theta and theta -6 are both acute angles fing the value of theta
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let theta be x
sin3x = cos x-6
cos(90-3x) = cos(x-6)
90-3x = x-6
96/4 = x
x = 24
Hope it helps u :-)
sin3x = cos x-6
cos(90-3x) = cos(x-6)
90-3x = x-6
96/4 = x
x = 24
Hope it helps u :-)
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