Math, asked by melchizedek1427, 1 year ago

If sin3A=cos(A-10°).Find A

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Answered by saurabhsemalti
1

 \sin(3a)  =  \cos( a - 10)  \\  \sin(3a)  =  \sin( \frac{\pi}{2} - (a - 10) )  \\ compare \\ 3a =  \frac{\pi}{2}  - a + 10 \\ 4a =  \frac{\pi}{2}  + 10 \\ a =  \frac{\pi + 20}{8}

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