Question

If sin3A=cos(A−10° ), where 3A is an acute angle, then ∠A=......

Answer 1

Answer:

ANSWER

sin3A=cos(A−10

o

)⇒cos(90

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−3A)=cos(A−10

o

)

⇒90

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+10

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=3A+A⇒100

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=4A⇒A=25

o

Therefore, Answer is 25

o

Answer 2

Step-by-step explanation:

sin3A = cos(A-10)

cos(90-3A)= cos(A-10)

90-3A=A-10

A=25