If sin3A=cos(A−10° ), where 3A is an acute angle, then ∠A=......
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Answered by
1
Answer:
ANSWER
sin3A=cos(A−10
o
)⇒cos(90
o
−3A)=cos(A−10
o
)
⇒90
o
+10
o
=3A+A⇒100
o
=4A⇒A=25
o
Therefore, Answer is 25
o
Answered by
1
Step-by-step explanation:
sin3A = cos(A-10)
cos(90-3A)= cos(A-10)
90-3A=A-10
A=25
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