If sin3A= cos(A-14°), when 3A is an acute angle. Find the value of A.
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Answer:
sin 3A=cos(A-14)
sin3A=sin(90-(A-14))
3A=90-A+14
3A+A=104
4A=104
A=104/4
A=26 ...ans.
Answered by
0
Answer:
sin 3A = cos (A-14)
cos (90-3A) = cos (A-14)
(90-3A) = (A-14)
3A +A = 90+14
4A = 104
A = 104/4
A = 26
I hope it help you
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