Question

If sin3A= cos(A-14°), when 3A is an acute angle. Find the value of A.​

Answer 1

Answer:

sin 3A=cos(A-14)

sin3A=sin(90-(A-14))

3A=90-A+14

3A+A=104

4A=104

A=104/4

A=26 ...ans.

Answer 2

Answer:

sin 3A = cos (A-14)

cos (90-3A) = cos (A-14)

(90-3A) = (A-14)

3A +A = 90+14

4A = 104

A = 104/4

A = 26

I hope it help you