Math, asked by krishharun35pbeb49, 11 months ago

if sin3A = cos(A-26). Then A=

Answers

Answered by Sreekar273
8

Answer:

29

Step-by-step explanation:

sin3A=cos(A-26)

sin3A=sin(90-(A-26))

sin3A=sin(90+26-A)

sin3A=sin(116-A)

Therefore,

3A=116-A

4A=116

A=29

Answered by siddhartharao77
5

Answer:

A = 29°

Step-by-step explanation:

Given: sin3A = cos(A - 26)

We know that cos(90 - θ) = sinθ

⇒ sin 3A = sin(90 - (A - 26))

⇒ sin 3A = sin(90 - A + 26)

⇒ 3A = 90 - A + 26

⇒ 3A + A = 90 + 26

⇒ 4A = 116

⇒ A = 116/4

⇒ A = 29.


Therefore,A = 29°.


Hope it helps!


VijayaLaxmiMehra1: Well explained answer sir!
siddhartharao77: Thank you
Similar questions