if sin3A=cos(A-6),where3Aand(A-6)are acute angles,then the value of A
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2
Answer:
The answer is 24°
Step-by-step explanation:
sin3A=cos(A-6°)
cos(90°-3A)=cos(A-6°)
90°-3A=A-6°
4A=96
A=24°
Answered by
1
Answer:
the value of a is 24 hope i think I am correct
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