Question

If sin4=3/5 find sec²A-tan²A​

Answer 1

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Answer 2

Answer:

If sinA=3/ 5 then

sin^2A+cos^A=1

9/25+cos^2A=1

cos^2A=1-9/25

cos^2A=16/25

cosA=4/5

and tanA=sinA/cosA

So, tanA=3/4

and secA=1/cosA

So, secA=5/4

Now, sec^2A-tan^2A=(25/16)-(9/16)

=16/16=1

Hence, answer is 1