if sin5A=cos4A, where 5A and 4A are acute angles, find the value of A?
Answers
Answered by
98
sin 5A =cos 4A
we know sin (90-@) =cos@
use this
sin 5A = sin (90-4A)
5A = 90 -4A
9A = 90
A= 10
we know sin (90-@) =cos@
use this
sin 5A = sin (90-4A)
5A = 90 -4A
9A = 90
A= 10
Answered by
62
according to the question :
sin a = cos(90-a)
sin 5a= cos 4a
so, sin 5a = cos ( 90 - 4a)
5a = ( 90 - 4a )
5a + 4a = 90
9a = 90
so, a = 10
the value of a = 10 hope it will help is so thn plzz mark it as a brainleist one ^_^
sin a = cos(90-a)
sin 5a= cos 4a
so, sin 5a = cos ( 90 - 4a)
5a = ( 90 - 4a )
5a + 4a = 90
9a = 90
so, a = 10
the value of a = 10 hope it will help is so thn plzz mark it as a brainleist one ^_^
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