Question

If sinA=1/2, then find the value of cosA.

Answer 1

√3/2 is the answer .... hope it helps u

Answer 2

☆☆HEYA MATE, HERE IS UR ANSWER ________☆☆

$\huge\boxed {\pink {\bold {ANSWER}}}$

SinA=1/2

=P/H

Let the constant be k.

P/H=1k/2k

P=k and H=2k

$\underline{\green {\bold{By\:PGT}}}$

H^2=P^2+B^2

(2k)^2=K^2+B^2

4k^2=K^2+B^2

4k^2-k^2=B^2

K^2 (4-1)=B^2

$\sqrt {k^2 (3)}$=B

k $\sqrt {3}$=B

So base =k $\sqrt {3}$

Cos A=B/H

$\underline{\red {\bold{CosA}}}$=k $\sqrt {3}$/2k

=$\sqrt {3}$/2

$\mathbb{Be\:Brainly}$