Question

If SinA =1/2 verify 2sinAcosA =2tanA/1+tansquareA

Answer 1

Answer:

No answer. Just check the solution!

Step-by-step explanation:

SinA = 1/2

SinA = P/H

Let P = k

Then, H = 2k

By Pythagoras Theorem,

H² = P² + B²

B² = H² - P²

B = √(H² - P²) = √[(2k)^2 - (k)²] = √[4k² - k²] = k√3

Given: SinA = 1/2

CosA = B/H = k√3/2k = √3/2

TanA = P/B = k/k√3 = 1/√3 = √3/3

To Prove: 2sinAcosA = 2tanA/(1 + tan²A)

LHS = 2 sinA cosA = 2 × 1/2 × √3/2 = √3/2

RHS = 2 tanA / (1 + tan²A) = (2 × √3/3) ÷ (1 + (√3/3)²) = (2√3/3) ÷ (1 + 3/9) = (2√3/3) ÷ (1 + 1/3) = (2√3/3) ÷ ((3+1)/3) = (2√3/3) ÷ (4/3) = 2√3/3 × 3/4 = √3/2

LHS = RHS

Hence Proved.

Answer 2

Answer:

Step-by-step explanation:I don't know