If sinA=1/2(x+1/x), then prove that sin3A+1/2(x^3+1/x^3)=0
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Step-by-step explanation:
Take, A =sin-¹(1/2)= 30°
Now Sin (3A)= Sin (3*30°)
=Sin (90°)
=1
Just simple like that
Alternatively, if the angle is in second quadrant, A = 180–30=150°
Then, Sin(3A) =Sin( 3*150)=Sin (450°)
= Sin(450–360)
=Sin (90°)
=1
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