Question

if sinA=1/√3, calculate CosA and tanA.


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Answer 1

Step-by-step explanation:

sinA=1/√3

then

by Pythagoras theorem we will find base b

(H)²=(B)²+(P)²

(√3)²=B²+(1)²

B²=3-1

B=√2

Cos A=b/h

=√2/√3

Tan A=p/b

=1/√2

Answer 2

Answer:

Cos A = root2 / root3.

Tan A = 1/root 2.

Step-by-step explanation:

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