Question

If sinA = 1/3 find cos A​

Answer 1

Answer:

Kindly refer to the attachment

Answer 2

Answer:

SinA = opp/hyp ==> 1/3

CosA = adj/hyp ==> adj/3

Opp= 1 hyp = 3 adj = ?

adj = \sqrt{hyp^2-opp^2}hyp2−opp2

adj = \sqrt{3^2 -1^2}32−12

adj = \sqrt{9-1}9−1

adj = \sqrt{8}8

adj = 2\sqrt{2}22

THEREFORE CosA = 2√2/3