Question

If sinA=1/3 ,then find the value of sin A *cos*2A+ cot*2A+cosecA...​

Answer 1

Answer:

given,

sinA=1/3=opp/hyp

cosA=adj/hyp=2√2/3

cot2A=1/tan2A

so,tan2A=2tanA/1-tan^A

tanA=1/2√2

so,cot2A=1-tan^A/2tanA

cos2A=2cos^A-1

cosecA=3

by substituting the values in the question we have,

Ans: -11√32+189+81√3/108√2

hope,it helps you.