Math, asked by yogambaraswal, 11 months ago

If sinA=1/3x and tanA=x/3 then find the value of x^2 - 1/x^2

Answers

Answered by jayjeetchakraborty39
12

Step-by-step explanation:

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Answered by dk6060805
14

2Sin^2 \frac {A}{2} is the value

Step-by-step explanation:

Given, Sin A  = \frac {1}{3x}\ and\ tan A = \frac {x}{3}

As tan A = \frac {x}{3}

\frac {Sin A}{Cos A} = \frac {x}{3}

\frac {1}{3x Cos A} = \frac {x}{3}

\frac {1}{xCos A} = x

Cos A = \frac {1}{x^2} """(1)

So, value of x^2 - \frac {1}{x^2} is-

= 1 - \frac {1}{x^2}

= 1 - Cos A [from (1)]

= 1 - 1 + 2Sin^2 \frac {A}{2}

= 2Sin^2 \frac {A}{2}

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