Question

if sinA=1/3x and tanA=x/3 then find the value of (x^2-1/x^2)​

Answer 1

Answer:

Step-by-step explanation:

sinA=1/3x

tanA=x/3

sin²A=1/9x²

=>9sin²A=1/x²..._____________________(1)

tan²A=x²/9

=>9tan²A=x²_______________________(2)

subtracting(1) from (2),

x²-i/x²=9tan²A-9sin²A

=>9(tan²A-sin²A) = 9[(sin²A/cos²A)-sin²A]

=>9(sin²A-sin²Acos²A)/cos²A

=>9(sin²A(1-cos²A)/cos²A)

=>9sin⁴A/cos²A = 9tan²Asin²A

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