Question

If sinA =1/3x and tanA=x/3 then find the value of xsquare -1/xsquare

Answer 1

x²  - 1/x² = 1/9  If sinA =1/3x and tanA=x/3

Step-by-step explanation:

SinA = 1/3x

TanA  = x/3

CosA = SinA/TanA

=> CosA  = (1/3x)/(x/3)

=> CosA = 1/x²

=> x² = 1/CosA

x²  - 1/x²

= 1/CosA  -  CosA

= (1 - Cos²A)/CosA

= Sin²A/CosA

= SinA. TanA

= (1/3x) * (x/3)

= 1/9

x²  - 1/x² = 1/9

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Answer 2

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