Math, asked by kg0t4sudhaavarsh, 1 year ago

If sinA-1/sinA=3,find sin²A+1/sin²A

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Answered by 140536

0

sinA-1/sinA=3
squaring on both sides
sin^A+1/sin^2A - 2 = 9
sin^A+1/sin^2A = 9+2
sin^A+1/sin^2A = 11

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