Question

if sinA =3/4, calculate secA.​

Answer 1

$\huge \mathscr{\orange {\underline{\pink{\underline {Answer:-}}}}}$

GIVEN :-

SinA = ¾

TO PROVE :-

SecA

SOLUTION :-

If,

SinA = ¾

=> Perpendicular / Hypotenuse = ¾

=> Perpendicular = 3

Hypotenuse = 4

Applying Pythagoras Rule,

Perpendicular² + Base² = Hypotenuse²

=> Base² = Hypotenuse² - Perpendicular²

=> Base² = 4² - 3²

=> 16 - 9

=> 7

Base = √7 Units.

Now,

SecA = Hypotenuse / Base

SecA = 4/√7

Answer 2

$\huge{\underline{\underbrace{\mathcal\color{gold}{Answer}}}}$

GIVEN :-

$SinA = \frac{3}{4}$

TO PROVE :-

$SecA$

$\huge\bold{Solution}$

If,

SinA = ¾

=> Perpendicular / Hypotenuse = ¾

=> Perpendicular = 3

Hypotenuse = 4

Applying Pythagoras Rule,

$\boxed{\blue{Perpendicular² + Base² = Hypotenuse²}}$

=> Base² = Hypotenuse² - Perpendicular²

=> Base² = 4² - 3²

=> 16 - 9

=> 7

Base = √7 Units.

Now,

SecA = Hypotenuse / Base

${\fcolorbox{aqua}{navy}{\fcolorbox{yellow}{blue}{\bf{\color{yellow}{ SecA = 4/√7}}}}}$