Question

if sinA=3/4,then find tanP and cotR​

Answer 1

sin A =3/4, find tan P & cot R

we know identity of trigonometry

sin ^2 theta +tan^2 theta =1

(3/4)^2+tan ^2 theta =1

9/16 +tan ^2 theta =1

tan ^2 theta = 9/16 -1

tan ^2 theta = 9-16 /16

tan ^2 theta = -6 /16

tan theta = - under root 6 / 4

we know that

cot theta = 1/tan theta

hence cot theta = 4 /- under root 6

hence,

tan theta = - under root 6 /4

cot theta = 4/ - under root 6

hope it help & it will be right.