Question

if sinA =3/5 & CosA =4/5 find value of sin2A+cos2A​

Answer 1

Answer:

A=37°and B= 63°

And sin2A=2sinA*cosA

=2*3/5*4/5=24/25

Also

Cos2A=2cos^2-1

=2*16/25) - 1

=32/25)-1

=7/25

Now sin2A+cos2A=24/25+7/25=31/25 ans...

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