Question

If sinA=3/5 and cosB=5/13, find the value of sinB+cosA.​

Answer 1

Answer:

SinA = 3/5. and cosB = 5/13

CosA = 4/5 and sinB = 12/13

Sin(a + b) = sinA. cosB + cosa. sinB

Sin(a + b) = 3/5 * 5/13 + 4/5 * 12/13

Sin(a + b) = 15/65 + 48/65

Sin(a + b) = 63 / 65

Thanks

Step-by-step explanation:

Answer 2

Answer:

SinA = 3/5

CosB = 5/13

So, SinA + CosA

$\frac{3}{5} + \frac{5}{13}$

$\frac{39 + 25}{65}$

$\frac{64}{65}$