Math, asked by nishantsinghhh0, 9 months ago

If sinA= 3/5
then find the value of (tanA +secA)​

Answers

Answered by adamyjain60p7dqlr
1

Answer:

2

Step-by-step explanation:

Given,

SinA=3/5

SinA=P/H

P=3, H=5

P²+B²=H²

B=4

TanA=P/B=3/4

SecA=H/B=5/4

TanA+SecA=3/4+5/4=8/4=2

Answered by deve11
0

Step-by-step explanation:

If sinA=3/5(opp/hyp)

By Pythagoras theorem:

hyp²=opp²+adj²

5²-3²=25-9=√16=4=adj.

CosA=4/5.

tanA=3/4

secA=5/4

tanA+secA=3/4+5/4=3+5/4=8/4=2.

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